AQA · Chemistry · 8462
GCSE Chemistry: Use of amount of substance in relation to volumes of gases
Quantitative chemistry · AQA GCSE Chemistry (8462), specification point 4.3.5. Cards are generated from the exam board's own specification for "Use of amount of substance in relation to volumes of gases", and every card links back to the page it came from. Higher tier only. Separate science only. Specification © AQA — used with attribution.
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What is the volume of one mole of any gas at room temperature and pressure?
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24 dm³.
What temperature and pressure define room temperature and pressure (RTP) in GCSE chemistry?
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20 °C and 1 atmosphere pressure.
Equal amounts in moles of gases occupy the ? volume under the same conditions of temperature and pressure.
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same
Under what two conditions do equal moles of different gases occupy equal volumes?
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The same temperature and the same pressure.
How do you calculate the volume of a gas at RTP from its mass?
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Divide mass by relative formula mass to get moles, then multiply moles by 24 dm³.
What volume does 0.5 mol of any gas occupy at RTP?
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12 dm³ (0.5 × 24 dm³).
What volume does 4 g of hydrogen gas (H₂, Mr = 2) occupy at RTP?
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48 dm³ (4 ÷ 2 = 2 mol; 2 × 24 dm³).
What information is needed to calculate the volumes of gaseous reactants and products in a reaction?
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The balanced equation for the reaction (plus one known gas volume, all at the same temperature and pressure).
In 2H₂ + O₂ → 2H₂O, what volume of oxygen reacts with 40 dm³ of hydrogen at RTP?
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20 dm³ — the equation gives a 2:1 mole ratio, and equal moles of gas occupy equal volumes.
Rearrange volume = moles × 24 to make moles the subject.
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moles = volume ÷ 24 (volume in dm³ at RTP).
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