AQA · Mathematics · 8300
GCSE Maths: Graphs: histograms (interpret)
Statistics · AQA GCSE Maths (8300). Cards are generated from the Corbettmaths practice questions for Graphs: histograms (interpret) (Corbettmaths Video 158), and every card links back to the exact page it came from. Practice tests are drawn from this deck’s own cards. Source material © Corbettmaths — used with attribution.
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In a histogram, what does the area of a bar represent?
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The frequency (or number of items) in that class interval.
When reading a histogram with unequal class widths, why must you consider the bar's area rather than just its height?
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Because the frequency is represented by the area of the bar. Different class widths mean height alone does not accurately represent frequency.
To estimate the number of data points between two values that don't align with class boundaries in a histogram, what assumption do you make?
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Assume the data is evenly distributed within each class interval.
When estimating the median from a histogram, what value do you need to find first?
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The total frequency, then find the value at the (n/2)th position.
What formula defines the lower quartile position in a dataset of n values?
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The (n/4)th position or the value at 25% of the cumulative frequency.
What formula defines the upper quartile position in a dataset of n values?
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The (3n/4)th position or the value at 75% of the cumulative frequency.
The interquartile range is calculated as ?.
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upper quartile minus lower quartile
When estimating the mean from a histogram, what value should you use to represent each class interval?
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The midpoint (or middle value) of each class interval.
If you know the frequency for one bar in a histogram, how can you find frequencies for other bars?
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Calculate the frequency density (height) for the known bar, then use proportional reasoning based on the areas of other bars.
To find what percentage of data falls within a range on a histogram, what two values do you need?
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The frequency within that range and the total frequency, then calculate (frequency in range / total frequency) × 100.
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