AQA · Chemistry · 8462

GCSE Chemistry: Using concentrations of solutions in mol/dm3

Quantitative chemistry · AQA GCSE Chemistry (8462), specification point 4.3.4. Cards are generated from the exam board's own specification for "Using concentrations of solutions in mol/dm3", and every card links back to the page it came from. Higher tier only. Separate science only. Specification © AQA — used with attribution.

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  1. What unit expresses concentration as amount of substance per volume?

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    mol/dm³ (moles of solute per cubic decimetre of solution).

  2. What is the equation for concentration in mol/dm³?

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    concentration (mol/dm³) = amount of solute (mol) ÷ volume of solution (dm³).

  3. How do you calculate moles of solute from concentration and volume?

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    moles = concentration (mol/dm³) × volume (dm³).

  4. How do you convert a volume in cm³ to dm³?

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    Divide by 1000 (1 dm³ = 1000 cm³).

  5. How do you find the mass of solute from its amount in moles?

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    mass (g) = moles × relative formula mass (Mr).

  6. To convert a concentration from g/dm³ to mol/dm³, divide by the ?.

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    relative formula mass

  7. How many moles are in 250 cm³ of 0.5 mol/dm³ solution?

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    0.125 mol (0.5 × 0.250 dm³).

  8. What data is needed to find an unknown concentration from a titration?

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    The volumes of both reacting solutions, the concentration of one of them, and the reaction's mole ratio from the balanced equation.

  9. Which practical technique determines the concentration of a strong acid or alkali?

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    Titration — reacting it completely with a solution of known concentration.

  10. Why must volume be in dm³ when using concentration in mol/dm³?

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    Because the concentration is defined per dm³, so the units must match for moles = concentration × volume to be correct.

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