AQA · Mathematics · 8300

GCSE Maths: Probability: independent events

Probability · AQA GCSE Maths (8300). Cards are generated from the Corbettmaths textbook exercise and practice questions for Probability: independent events (Corbettmaths Video 249), and every card links back to the exact page it came from. Practice tests are drawn from this deck’s own cards. Source material © Corbettmaths — used with attribution.

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  1. What is the formula for the probability of two independent events both occurring?

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    Multiply the individual probabilities: P(A and B) = P(A) × P(B)

  2. What is the probability of a fair coin landing on heads twice in two flips?

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    1/4 (or 0.25). Calculate as (1/2) × (1/2) = 1/4

  3. If a fair six-sided dice is rolled three times, what is the probability of getting a six all three times?

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    1/216. Calculate as (1/6) × (1/6) × (1/6) = 1/216

  4. Why does replacing an item before selecting again ensure events are independent?

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    Replacement restores the original probabilities, so the outcome of the first selection does not affect the second selection

  5. If event A has probability 0.7 and event B has probability 0.4, what is the probability both occur (assuming independence)?

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    0.28. Calculate as 0.7 × 0.4 = 0.28

  6. If the probability of an event occurring is p, what is the probability of it NOT occurring?

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    1 - p (the complement probability)

  7. If the probability of hitting a bullseye is 0.3, what is the probability of NOT hitting the bullseye with two darts?

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    0.49. Calculate as 0.7 × 0.7 = 0.49 (where 0.7 is the probability of missing)

  8. If a biased coin has probability 0.7 of landing on tails, what is the probability it lands on heads twice in two flips?

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    0.09. Calculate as 0.3 × 0.3 = 0.09 (where 0.3 = 1 - 0.7 is the probability of heads)

  9. What does 'at least one' mean when calculating probabilities?

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    One or more occurrences. Often easier to calculate as 1 minus the probability of none occurring

  10. If a fair dice is rolled three times, what is the probability of getting NO sixes?

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    125/216. Calculate as (5/6) × (5/6) × (5/6) = 125/216

  11. How do you find the probability of 'exactly once' in multiple independent trials?

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    Use the binomial approach: multiply the probability of one success and all other failures, then multiply by the number of ways to arrange that outcome.

  12. What does 'at least two' mean when calculating probabilities?

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    Two or more. It includes exactly two, exactly three, etc., up to all possible occurrences.

  13. If three independent events have probabilities 4/5, 2/3, and 3/4, what is the probability all three occur?

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    (4/5) × (2/3) × (3/4) = 2/5 or 0.4

  14. What is the complement of 'all three dice show a 6'?

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    At least one die does not show a 6 (or equivalently, none of them all show 6).

  15. If the probability that all 3 biased dice show a 6 is 0.343, and each die is identical, what is the probability one die shows a 6?

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    0.7, because 0.7³ = 0.343, so P(one die shows 6) = ∛0.343 = 0.7

  16. When finding if a score from multiple independent trials is even, what strategy should you use?

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    Consider the parity (odd/even) of each outcome and determine which combinations sum to an even number.

  17. If beads are in the ratio 1:3 (yellow to green), what is the probability of selecting a yellow bead?

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    1/4, because there is 1 yellow for every 4 total beads (1 yellow + 3 green).

  18. If a spinner lands on blue twice with probability 9/400, what is the probability it lands on blue once?

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    3/20 (or 0.15), because if P(blue)² = 9/400, then P(blue) = √(9/400) = 3/20.

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