AQA · Mathematics · 8300
GCSE Maths: Graphs: conversion graphs (draw)
Statistics · AQA GCSE Maths (8300). Cards are generated from the Corbettmaths textbook exercise and practice questions for Graphs: conversion graphs (draw) (Corbettmaths Video 151), and every card links back to the exact page it came from. Practice tests are drawn from this deck’s own cards. Source material © Corbettmaths — used with attribution.
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When using a conversion graph, how do you convert from one unit to another?
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Read the value on one axis (e.g., horizontal), find the corresponding point on the conversion line, then read across to the other axis (e.g., vertical) to find the converted value.
The approximation ? is commonly used for distance conversions.
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5 miles ≈ 8 kilometres
What axes labels would you use when drawing a conversion graph between UK pounds and a foreign currency?
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One axis (typically horizontal) shows UK pounds, the other axis (typically vertical) shows the foreign currency amount.
When converting a value beyond the range shown on a conversion graph, what mathematical approach should you use?
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Extend the linear relationship by multiplying the conversion rate. For example, if the graph shows up to 10 units, use proportional scaling to convert larger values.
Why are conversion graphs always drawn as straight lines through the origin?
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Because the relationship between the two quantities is proportional (linear) – zero of one unit equals zero of the other, and the rate of conversion is constant.
In the UK system, 1 stone equals ? pounds.
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14
When comparing prices in different currencies using conversion graphs, what steps are needed?
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Convert both prices to the same currency using the conversion graph(s), then compare the converted values to determine which is cheaper and by how much.
The exchange rate given for pounds to Indian rupees is £1 = ?.
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90 Rupees
What information is needed to draw a conversion graph between two units?
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The conversion rate (e.g., £1 = 90 Rupees or 5 miles = 8 km) and the range/scale for each axis. The graph is a straight line through the origin using this rate.
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