AQA · Mathematics · 8300

GCSE Maths: Quadratic nth term – Version 2

Algebra · AQA GCSE Maths (8300). Cards are generated from the Corbettmaths textbook exercise and practice questions for Quadratic nth term – Version 2 (Corbettmaths Video 388), and every card links back to the exact page it came from. Practice tests generate fresh variations of these questions, so the numbers change every attempt. Source material © Corbettmaths — used with attribution.

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  1. What is constant in a quadratic sequence?

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    The second difference (the difference between consecutive first differences).

  2. Which of these is a quadratic sequence: 1, 1, 2, 3, 5 / 1, 3, 9, 27 / 1, 5, 11, 19, 29 / 1, 11, 21, 31?

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    1, 5, 11, 19, 29, … — its first differences (4, 6, 8, 10) increase by a constant 2, so the second difference is constant.

  3. In a quadratic sequence, the coefficient of n² equals ? the second difference.

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    half

  4. What is the next term of the quadratic sequence 7, 11, 17, 25, …?

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    35. First differences 4, 6, 8 grow by 2, so the next difference is 10 and 25 + 10 = 35.

  5. What are the first three terms of the sequence with nth term n² − 2n + 8?

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    7, 8, 11 (substitute n = 1, 2, 3).

  6. What is the 10th term of the sequence with nth term 3n² − 8n − 20?

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    200. 3(100) − 80 − 20 = 200.

  7. Which term of the sequence n² − 6n + 7 has the value 23?

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    The 8th term. Solve n² − 6n − 16 = 0 → (n − 8)(n + 2) = 0, and n must be positive.

  8. Find the nth term of the quadratic sequence 4, 10, 18, 28, 40, …

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    n² + 3n. Second difference 2 → n²; subtracting n² leaves 3, 6, 9, 12, 15 = 3n.

  9. Find the nth term of the quadratic sequence 9, 17, 29, 45, 65, …

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    2n² + 2n + 5. Second difference 4 → 2n²; subtracting 2n² leaves 7, 9, 11, 13, 15 = 2n + 5.

  10. Find the nth term of the quadratic sequence 7, 5, 1, −5, …

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    −n² + n + 7. Second difference −2 → −n²; adding n² back gives 8, 9, 10, 11 = n + 7.

  11. What is the 100th term of the quadratic sequence −5, −4, 3, 16, 35, …?

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    29 200. The nth term is 3n² − 8n, so 3(10 000) − 800 = 29 200.

  12. In the sequence n² + 3n, two consecutive terms differ by 38. What are their positions?

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    17 and 18. The difference between term n+1 and term n is 2n + 4, so 2n + 4 = 38 gives n = 17.

  13. For the nth term an² + c, what equation does the 2nd term give?

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    4a + c = (second term), because substituting n = 2 gives a(2)² + c = 4a + c.

  14. For the nth term an² + c, what equation does the 5th term give?

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    25a + c = (fifth term), because substituting n = 5 gives a(5)² + c = 25a + c.

  15. How do you find a and c in an² + c given two terms?

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    Substitute each term's position n to get two simultaneous equations, then subtract them to eliminate c and solve for a.

  16. A sequence has nth term an² + c. Its 2nd term is 16 and 5th term is 163. Find a.

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    a = 7. Subtract 4a + c = 16 from 25a + c = 163 to get 21a = 147.

  17. A sequence has nth term an² + c. Its 2nd term is 16 and 5th term is 163. Find c.

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    c = −12. With a = 7, substitute into 4a + c = 16: 28 + c = 16.

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